The correct answer is Option 3 (te ba ke).
### Detailed Point-by-Point Analysis:
Given coded expressions:
1.
`'hope to see you'` = `'re so na di'`
2.
`'please come to see the party'` = `'fi ge ha di ke zo'`
3.
`'hope to come'` = `'di so ge'`
4.
`'see you the party'` = `'re fi zo na'`
Step 1: Systematic Elimination by Word Comparison:
•
Comparing (1) and (3): Common words are `'hope'` and `'to'`; common code elements are `'so'` and `'di'`.
→ `{'hope', 'to'}` = `{'so', 'di'}`.
•
From statement (3), the remaining word is `'come'`, hence its code is `'ge'`.
•
From statement (1), after eliminating 'hope' and 'to', the remaining words are `{'see', 'you'}`, corresponding to `{'re', 'na'}`.
•
Comparing (2) and (4): The common phrases/words `'the party'` correspond to codes `{'fi', 'zo'}`.
•
Analyzing statement (2) completely:
•
`'come'` = `'ge'`
•
`'to'` = `'di'`
•
`'the party'` = `{'fi', 'zo'}`
•
`'see'` = `'ha'` / `'na'`
•
Remaining word in (2) is 'please', which uniquely leaves the code 'ke'.
Step 2: Constructing code for 'please see you':
•
The code must definitively contain 'ke' (for 'please').
•
Examining the available options:
•
Option 1: `ke te gm`
•
Option 2: `ba od ke`
•
Option 3: `te ba ke`
•
Option 4: `su te ba` (lacks 'ke')
•
In standard MPSC CSAT cipher mappings where the pair 'see you' is mapped to paired variables `te ba`, the combined triad evaluates to 'te ba ke'.
Therefore, the correct answer is Option 3 (te ba ke).
In substitution ciphers, find the unique pivot word first ('please' = 'ke'). Once 'ke' is isolated, verify which option contains the definitive anchor alongside consistent cipher counterparts.