सोडवा \(\frac{(3.49)^{2}-(0.51)^{2}}{3.49-0.51}\)
📐 वापरलेले सूत्र (Formula Used):
बीजगणितीय नित्यसमीकरण: a² - b² = (a + b)(a - b)
त्यामुळे (a² - b²) / (a - b) = a + b
येथे a = ३.४९ आणि b = ०.५१
मूल्य = ३.४९ + ०.५१ = ४.००.
Given:
\(\dfrac{(3.49)^2-(0.51)^2}{(3.49-0.51)}\) = ?
Formula used:
\(\dfrac{a^2-b^2}{a-b} = [(a+b)(a-b)]/(a-b) = (a+b)\)
Calculation:
\(\dfrac{(3.49)^2-(0.51)^2}{(3.49-0.51)}\) = ?
⇒ \(\dfrac{a^2-b^2}{a-b} = a+b\)
⇒ ? = 3.49 + 0.51
⇒ ? = 4
∴ The correct answer is option (1).
दशांशातील पदावली सोडवताना प्रत्यक्ष गुणाकार/वर्ग न करता a² - b² = (a + b)(a - b) सारखी नित्यसमीकरणे वापरल्यास उत्तर २ सेकंदात येते.
📐 Formula Used:
Algebraic Identity: a² - b² = (a + b)(a - b)
Therefore: (a² - b²) / (a - b) = a + b
Here a = 3.49, b = 0.51 ⟹ 3.49 + 0.51 = 4.00.
Given:
\(\dfrac{(3.49)^2-(0.51)^2}{(3.49-0.51)}\) = ?
Formula used:
\(\dfrac{a^2-b^2}{a-b} = [(a+b)(a-b)]/(a-b) = (a+b)\)
Calculation:
\(\dfrac{(3.49)^2-(0.51)^2}{(3.49-0.51)}\) = ?
⇒ \(\dfrac{a^2-b^2}{a-b} = a+b\)
⇒ ? = 3.49 + 0.51
⇒ ? = 4
∴ The correct answer is option (1).
Recognize the algebraic identity (a² - b²) / (a - b) = a + b to avoid tedious squaring and subtraction.